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Calculations of δ

      Transformation of IJK basis to SEZ basis
[arrow drawn connecting]geocentric  topocentric-horizon
                        equatorial    coordinate system
                          basis


[note on left margin]                     
these two { (i) rotate about k axis by Θ
rotations { (ii) rotate through 90-L about J axis
bring                        (for a better picture, see Fundamentals of
the IJK                                   Astrophysics p.100)
basis into angular
alignment
w/ the SEZ
basis

[drawing]

(Vi,Vj,Vk)=velocity of shuttle in IJK system
(Vs,Ve,Vz)=velocity of shuttle in SEZ system

(1) Θ rotation matrix          (ii) 90-L rotation matrix
    (cosΘ sinΘ 0                    (sinL 0 -cosL
    -sinΘ cosΘ 0                      0   1   0
      0    0   1)                    cosL 0 sinL)

(Vs    (sinL 0 -cosL    (cosΘ sinΘ 0   (Vi
 Ve  =   0   1   0      -sinΘ cosΘ 0    Vj
 Vz)    cosL 0 sinL)      0    0   1)   Vk)

(Vs    (sinLcosΘ  sinLsinΘ -cosL       (Vi
 Ve  =   -sinΘ      cosΘ     0          Vj
 Vz)    cosLcosΘ  cosLsinΘ  sinL)       Vk)

(Vs    (sinLcosΘVj+sinLsinΘVj-cosLVk
 Ve  =  -sinΘVi+cosΘVj
 Vz)    cosLcosΘVi+cosLsinΘVj+sinLVk)

Because δ is the angle between north and the local
horizontal, it is convenient to transform (Vs,Ve,Vz) to
(Vn,Ve,Vz). To do this Vs-->Vn   Vn=-Vs

                                               cont'd