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Calculations of δ Transformation of IJK basis to SEZ basis [arrow drawn connecting]geocentric topocentric-horizon equatorial coordinate system basis [note on left margin] these two { (i) rotate about k axis by Θ rotations { (ii) rotate through 90-L about J axis bring (for a better picture, see Fundamentals of the IJK Astrophysics p.100) basis into angular alignment w/ the SEZ basis [drawing] (Vi,Vj,Vk)=velocity of shuttle in IJK system (Vs,Ve,Vz)=velocity of shuttle in SEZ system (1) Θ rotation matrix (ii) 90-L rotation matrix (cosΘ sinΘ 0 (sinL 0 -cosL -sinΘ cosΘ 0 0 1 0 0 0 1) cosL 0 sinL) (Vs (sinL 0 -cosL (cosΘ sinΘ 0 (Vi Ve = 0 1 0 -sinΘ cosΘ 0 Vj Vz) cosL 0 sinL) 0 0 1) Vk) (Vs (sinLcosΘ sinLsinΘ -cosL (Vi Ve = -sinΘ cosΘ 0 Vj Vz) cosLcosΘ cosLsinΘ sinL) Vk) (Vs (sinLcosΘVj+sinLsinΘVj-cosLVk Ve = -sinΘVi+cosΘVj Vz) cosLcosΘVi+cosLsinΘVj+sinLVk) Because δ is the angle between north and the local horizontal, it is convenient to transform (Vs,Ve,Vz) to (Vn,Ve,Vz). To do this Vs-->Vn Vn=-Vs cont'd