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calculation of δ cont'd (VN VE VZ)= (-sinLcosθvi-sinLsinθvj+cosLvk -sinθvi+cosθvj cosLcosθvi+cosLsinθvj+sinLvk) velocity= (VN, VE, VZ) [[image 1]] ground track [[image 2]] tanδ= VE/VN δ=tan-1(-sinθvi+cosθvj/-sinLcosθvi-sinLsinθvj+cosLvk) L=nadir latitude θ=θg+λE λE= nadir longitude measured east from the prime meridian (if nlong<) λE=18+nlong) θg=angle between prime meridian and Iaxis (pointing in direction of vernal equinox) in general, θg=θgo + correction term(s) θgo= angle between vernal equinox and prime meridian on Jan 1 (Julian date) of year that velocity is measured Because the shuttle's coordinates are given to us in the B1950 coordinate system, θg is fixed and θg= θgo. Coordinate system B1950: ___ vernal equinox direction on Jan 1, 1950. So, to find θ (angle between and nlongitude, we need θ= θgo + λE= (vernal equinox -> Greenwich) + (nlongitude)
Transcription Notes:
Image 1 is a wave graph with the Y axis labeled N and the X axis labeled E
Image 2 is a triangle with an angle labeled δ. Opposite side of triangle labeled VE and adjacent side labeled VN.