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74.

giving, for the kinetic energy per gram of mass expelled,

^[[v [[superscript]] 2 [[/superscript]]/2 = (M + Ms/3)(m[[subscript]] 1 [[/subscript]]g)/2Mo[[superscript]] 2 [[/superscript]] s[[superscript]] 2 [[/superscript]].

From this it is possible to obtain the efficiency, by dividing by the heat value of the powder, in ergs; and also the velocity in kilometers per second by multiplying by two, extracting the square root, and dividing by 10[[superscript]] 5 [[/superscript]].

[[underlined]] CORRECTION OF THE DISPLACEMENT, s, FOR FRICTION [[/underlined]].

The displacement, [[underlined]] s [[/underlined]], in the preceding calculation is assumed to be the corrected displacement. This is obtained from the upward displacement [[underlined]] s [[/underlined]][[subscript]] 1 [[/subscript]], and the downward displacement s[[subscript]] 2 [[/subscript]], as

^[[s = s[[subscript]] 1 [[/subscript]] √s[[subscript]] 1 [[/subscript]]/s[[subscript]] 2 [[/subscript]].]]